86 lines
1.7 KiB
Plaintext
86 lines
1.7 KiB
Plaintext
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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Self powers (Euler Problem 48)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {
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"collapsed": true
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},
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"source": [
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"[https://projecteuler.net/problem=48](https://projecteuler.net/problem=48)\n",
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"\n",
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"The series, $1^1 + 2^2 + 3^3 + ... + 10^{10} = 10405071317$.\n",
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"\n",
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"Find the last ten digits of the series, $1^1 + 2^2 + 3^3 + ... + 1000^{1000}$."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"Okay, this would be way harder in C/C++. In every language with long int support it is easy. See the number of people who have solved it."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 7,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"9110846700\n"
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]
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}
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],
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"source": [
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"s = int(str(sum([i**i for i in range(1, 1001)]))[-10:])\n",
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"assert(s == 9110846700)\n",
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"print(s)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {
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"collapsed": true
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},
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"outputs": [],
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"source": []
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}
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],
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"metadata": {
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"completion_date": "Sun, 23 Dec 2018, 00:32",
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python3.6",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.6.5"
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},
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"tags": [
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"brute force",
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"self power"
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]
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},
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"nbformat": 4,
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"nbformat_minor": 2
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}
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