{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Self powers (Euler Problem 48)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {
    "collapsed": true
   },
   "source": [
    "[https://projecteuler.net/problem=48](https://projecteuler.net/problem=48)\n",
    "\n",
    "The series, $1^1 + 2^2 + 3^3 + ... + 10^{10} = 10405071317$.\n",
    "\n",
    "Find the last ten digits of the series, $1^1 + 2^2 + 3^3 + ... + 1000^{1000}$."
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Okay, this would be way harder in C/C++. In every language with long int support it is easy. See the number of people who have solved it."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "9110846700\n"
     ]
    }
   ],
   "source": [
    "s = int(str(sum([i**i for i in range(1, 1001)]))[-10:])\n",
    "assert(s == 9110846700)\n",
    "print(s)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": []
  }
 ],
 "metadata": {
  "completion_date": "Sun, 23 Dec 2018, 00:32",
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   "nbconvert_exporter": "python",
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  "tags": [
   "brute force",
   "self power"
  ]
 },
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