{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Convergents of e (Euler Problem 65)\n", "\n", "Hence the sequence of the first ten convergents for √2 are:\n", "\n", "1, 3/2, 7/5, 17/12, 41/29, 99/70, 239/169, 577/408, 1393/985, 3363/2378, ...\n", "\n", "What is most surprising is that the important mathematical constant,\n", "\n", "e = [2; 1,2,1, 1,4,1, 1,6,1 , ... , 1,2k,1, ...].\n", "\n", "The first ten terms in the sequence of convergents for e are:\n", "\n", "2, 3, 8/3, 11/4, 19/7, 87/32, 106/39, 193/71, 1264/465, 1457/536, ...\n", "\n", "The sum of digits in the numerator of the 10th convergent is 1+4+5+7=17.\n", "\n", "Find the sum of digits in the numerator of the 100th convergent of the continued fraction for e." ] }, { "cell_type": "code", "execution_count": 1, "metadata": {}, "outputs": [], "source": [ "def gcd(a, b):\n", " if b > a:\n", " a, b = b, a\n", " while a % b != 0:\n", " a, b = b, a % b\n", " return b\n", "\n", "def add_fractions(n1, d1, n2, d2):\n", " d = d1 * d2\n", " n1 = n1 * (d // d1)\n", " n2 = n2 * (d // d2)\n", " n = n1 + n2\n", " p = gcd(n, d)\n", " return (n // p, d // p)\n" ] }, { "cell_type": "code", "execution_count": 2, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "272\n" ] } ], "source": [ "def next_expansion(previous_numerator, previous_denumerator, value):\n", " if previous_numerator == 0:\n", " return (value, 1)\n", " return add_fractions(previous_denumerator, previous_numerator, value, 1)\n", "\n", "e_sequence = [2] + [n for i in range(2, 1000, 2) for n in (1, i, 1)]\n", "\n", "n, d = 0, 1\n", "\n", "for i in range(100, 0, -1):\n", " n, d = next_expansion(n, d, e_sequence[i - 1])\n", "\n", "s = sum([int(l) for l in str(n)])\n", "print(s)\n", "assert(s == 272)" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [] } ], "metadata": { "completion_date": "Wed, 23 Jan 2019, 05:54", "kernelspec": { "display_name": "Python 3", "language": "python3.6", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.6.5" }, "tags": [ "expansion", "e", "sequence" ] }, "nbformat": 4, "nbformat_minor": 2 }