{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Prime pair sets (Euler Problem 60)" ] }, { "cell_type": "markdown", "metadata": { "collapsed": true }, "source": [ "[https://projecteuler.net/problem=60](https://projecteuler.net/problem=60)\n", "\n", "The primes 3, 7, 109, and 673, are quite remarkable. By taking any two primes and concatenating them in any order the result will always be prime. For example, taking 7 and 109, both 7109 and 1097 are prime. The sum of these four primes, 792, represents the lowest sum for a set of four primes with this property.\n", "\n", "Find the lowest sum for a set of five primes for which any two primes concatenate to produce another prime.\n" ] }, { "cell_type": "code", "execution_count": 1, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "[[3, 7], [7, 3], [3, 109], [109, 3], [3, 673], [673, 3], [7, 109], [109, 7], [7, 673], [673, 7], [109, 673], [673, 109]]\n" ] } ], "source": [ "from itertools import combinations\n", "\n", "def concatenate_all(numbers):\n", " result = []\n", " for a, b in combinations(numbers, 2):\n", " result.append([a, b])\n", " result.append([b, a])\n", " return result\n", "\n", "print(concatenate_all([3, 7, 109, 673]))" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": true }, "outputs": [], "source": [ "def sieve_of_eratosthenes(limit):\n", " primes = []\n", " prospects = [n for n in range(2, limit)]\n", " while prospects:\n", " p = prospects[0]\n", " prospects = [x for x in prospects if x % p != 0]\n", " primes.append(p)\n", " if p * p > limit:\n", " break\n", " primes += prospects\n", " return primes\n", "\n", "primes = sieve_of_eratosthenes(100000)\n", "primes_set = set(primes)" ] }, { "cell_type": "code", "execution_count": 3, "metadata": {}, "outputs": [], "source": [ "def is_prime(n):\n", " if n % 2 == 0:\n", " return False\n", " while n % 2 == 0:\n", " n //= 2\n", " f = 3\n", " while f * f <= n:\n", " if n % f == 0:\n", " return False\n", " else:\n", " f += 2 \n", " return True\n", "\n", "def concatentation_is_prime(a, b):\n", " ab = int(str(a) + str(b))\n", " ba = int(str(b) + str(a))\n", " if is_prime(ab) and is_prime(ba):\n", " return True\n", " else:\n", " return False\n", " \n", "assert(concatentation_is_prime(673, 3))\n", "assert(concatentation_is_prime(673, 1) == False)" ] }, { "cell_type": "code", "execution_count": 4, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "[13, 5197, 5701, 6733, 8389]\n", "26033\n" ] } ], "source": [ "potentials = []\n", "new_potentials = []\n", "done = False\n", "for p in primes:\n", " if done:\n", " break\n", " potentials += new_potentials\n", " new_potentials = []\n", " for potential in potentials:\n", " all_concatenations_prime = True\n", " for prime in potential:\n", " if not concatentation_is_prime(p, prime):\n", " all_concatenations_prime = False\n", " break\n", " if all_concatenations_prime:\n", " new_potential = list(potential)\n", " new_potential.append(p)\n", " if len(new_potential) > 4:\n", " print(new_potential)\n", " s = sum(new_potential)\n", " done = True\n", " break\n", " new_potentials.append(new_potential)\n", " if p < 15:\n", " potentials.append([p])\n", "\n", "print(s)\n", "assert(s == 26033)" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [] } ], "metadata": { "completion_date": "Sun, 6 Jan 2019, 05:00", "kernelspec": { "display_name": "Python 3", "language": "python3.6", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.6.5" }, "tags": [ "prime", "pairs" ] }, "nbformat": 4, "nbformat_minor": 2 }