{
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   "source": [
    "# Powerful digit counts (Euler Problem 63)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {
    "collapsed": true
   },
   "source": [
    "The 5-digit number, 16807=$7^5$, is also a fifth power. Similarly, the 9-digit number, 134217728=$8^9$, is a ninth power.\n",
    "\n",
    "How many n-digit positive integers exist which are also an nth power?"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [],
   "source": [
    "def get_digit_count(n):\n",
    "    if n < 10:\n",
    "        return 1\n",
    "    c = 0\n",
    "    while n:\n",
    "        n //= 10\n",
    "        c += 1\n",
    "    return c\n",
    "\n",
    "assert(get_digit_count(0) == 1)\n",
    "assert(get_digit_count(1) == 1)\n",
    "assert(get_digit_count(33) == 2)\n",
    "assert(get_digit_count(100) == 3)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "49\n"
     ]
    }
   ],
   "source": [
    "def get_n_digit_positive_integers(n):\n",
    "    r = []\n",
    "    i = 1\n",
    "    while True:\n",
    "        if get_digit_count(i ** n) == n:\n",
    "            r.append(i ** n)\n",
    "        if get_digit_count(i ** n) > n:\n",
    "            return r\n",
    "        i += 1\n",
    "\n",
    "s = sum([len(get_n_digit_positive_integers(n)) for n in range(1, 1000)])\n",
    "print(s)\n",
    "assert(s == 49)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": []
  }
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 "metadata": {
  "completion_date": "Sun, 6 Jan 2019, 06:17",
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   "powers"
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