{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Euler Problem 20\n", "\n", "n! means n × (n − 1) × ... × 3 × 2 × 1\n", "\n", "For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800,\n", "and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.\n", "\n", "Find the sum of the digits in the number 100!" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Write our own factorial implementation and get the solution." ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": true }, "outputs": [], "source": [ "def factorial(n):\n", " assert(n > 0)\n", " if n == 1:\n", " return 1\n", " else:\n", " return n * factorial(n - 1)" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "648\n" ] } ], "source": [ "f100 = factorial(100)\n", "print(sum(map(int, str(f100))))\n", "assert(sum(map(int, str(f100))) == 648)" ] } ], "metadata": { "completion_date": "Fri, 5 Sep 2014, 10:42", "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.5.4" }, "tags": [ "factorial" ] }, "nbformat": 4, "nbformat_minor": 0 }