Euler Problem 31

In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation:

1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p).

It is possible to make £2 in the following way:

1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p

How many different ways can £2 be made using any number of coins?

I really have mental issues to this in a non recursive way. So here we go with recursion.

In [ ]:
def get_different_ways(remainder, coins):
    if not coins:
        return 1
    coin = coins[0]
    combinations = 1
    while remainder > 0: