{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Euler Problem 2\n", "\n", "Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be:\n", "\n", "1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...\n", "\n", "By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-valued terms." ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": true }, "outputs": [], "source": [ "def fibonacci_generator():\n", " a = 0\n", " b = 1\n", " while True:\n", " yield a + b\n", " a, b = b, (a + b)\n", " " ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Test fibonacci sequence generator by comparing the result to the example in the task statement." ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": true }, "outputs": [], "source": [ "i = fibonacci_generator()\n", "fib_10 = [next(i) for _ in range(10)]\n", "assert(fib_10 == [1, 2, 3, 5, 8, 13, 21, 34, 55, 89,])" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Greate a function which returns all even-valued fibonacci values smaller or equal to four million." ] }, { "cell_type": "code", "execution_count": 3, "metadata": { "collapsed": true }, "outputs": [], "source": [ "def get_even_fibonaccis_smaller_or_equal_four_million():\n", " r = []\n", " i = fibonacci_generator()\n", " current_value = next(i)\n", " while current_value <= 4000000:\n", " if current_value % 2 == 0:\n", " r.append(current_value)\n", " current_value = next(i)\n", " return r" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Calculate the solution." ] }, { "cell_type": "code", "execution_count": 4, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "4613732\n" ] } ], "source": [ "f = get_even_fibonaccis_smaller_or_equal_four_million()\n", "print(sum(f))" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "I looked at the solutions in the forum and I kind of forgot about simple straight forward approaches. There is no need to create a list and the sum it up. Instead I can simply increment a counter which will be much faster, but less readable maybe." ] }, { "cell_type": "code", "execution_count": 5, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "4613732\n" ] } ], "source": [ "r, a, b = 0, 0, 1\n", "while b <= 4000000:\n", " if b % 2 == 0: r += b\n", " a, b = b, a + b\n", "print(r)" ] } ], "metadata": { "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.5.4" } }, "nbformat": 4, "nbformat_minor": 2 }