{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Euler Problem 25\n", "\n", "The Fibonacci sequence is defined by the recurrence relation:\n", "\n", "$F_n = F_{n−1} + F_{n−2}$, where $F_1 = 1$ and $F_2 = 1$.\n", "Hence the first 12 terms will be:\n", "\n", "~~~\n", "F1 = 1\n", "F2 = 1\n", "F3 = 2\n", "F4 = 3\n", "F5 = 5\n", "F6 = 8\n", "F7 = 13\n", "F8 = 21\n", "F9 = 34\n", "F10 = 55\n", "F11 = 89\n", "F12 = 144\n", "~~~\n", "\n", "The 12th term, $F_{12}$, is the first term to contain three digits.\n", "\n", "What is the index of the first term in the Fibonacci sequence to contain 1000 digits?" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "Reuse fibonacci generator and then straight forward." ] }, { "cell_type": "code", "execution_count": 4, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "4782\n" ] } ], "source": [ "def fibonacci_generator():\n", " a = 0\n", " b = 1\n", " yield 1\n", " while True:\n", " yield a + b\n", " a, b = b, (a + b)\n", " \n", "for i, f in enumerate(fibonacci_generator()):\n", " if len(str(f)) >= 1000:\n", " break\n", "\n", "s = i + 1\n", "assert(s == 4782)\n", "print(s)" ] } ], "metadata": { "completion_date": "Fri, 5 Sep 2014, 14:57", "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.5.4" }, "tags": [ "fibonacci" ] }, "nbformat": 4, "nbformat_minor": 0 }