Solve problem 820
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@@ -0,0 +1,81 @@
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from math import floor
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from time import time_ns
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def d(_num: int, den: int, n: int) -> int:
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""" (10^n // d) % 10 -> (10^n % 10*d) // d % 10 """
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return pow(10, n, 10 * den) // den % 10
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def d_naiv(num: int, den: int, n: int, debug: bool = False) -> int:
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"""Return the nth digit of the factional part of num / den."""
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if num == den:
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if debug:
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print("1.0")
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return 0
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assert num < den
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if debug:
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print("0.", end="")
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x = None
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r = 0
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i = 0
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num *= 10 # 0.
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nums = {}
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while i < n:
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if num == 0:
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r = 0
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break
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elif num < den:
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r = 0
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if debug:
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print(0, end="")
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else:
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r = num // den
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num %= den
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if debug:
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print(r, end="")
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i += 1
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if x is None:
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if num in nums:
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j = nums[num]
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delta = i - j
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x = floor((n - i) / delta)
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if debug:
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print("---")
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print(f"{den=} {j} -> {i} (d={delta} mult={x})")
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print(f"\n{j} -{delta} {x}> {i} ")
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i += x * delta
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else:
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nums[num] = i
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num *= 10
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if debug:
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print()
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# dr = (10**n % (10*den)) // den
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dr = pow(10, n, 10 * den) // den
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assert r == dr
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# print(f"k = {den} n= {n}")
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return r
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def s(n: int) -> int:
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return sum(d(1, k, n) for k in range(1, n + 1))
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def euler_820():
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d(1, 7, 10)
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assert d(1, 2, 7) == 0
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assert d(1, 3, 7) == 3
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assert d(1, 5, 7) == 0
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assert d(1, 6, 7) == 6
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assert d(1, 7, 7) == 1
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assert s(7) == 10
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assert s(100) == 418
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assert s(10000) == 43742
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return s(10**7)
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if __name__ == "__main__":
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solution = euler_820()
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print(f"e820.py: {solution}")
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assert solution == 44967734
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