Solve problem 70 in Python.

main
Felix Martin 2019-07-21 14:13:28 -04:00
parent 66e4593c4b
commit c47970642a
11 changed files with 168 additions and 12 deletions

View File

@ -66,7 +66,7 @@ def euler_068():
if is_5_gon_ring(p):
r = five_gon_ring_to_group_presentation(p)
if len(r) == 16:
print(r)
# print(r)
rs.append(int(r))
return max(rs)

View File

@ -1,13 +1,4 @@
from lib_prime import primes
from lib_misc import gcd
def relative_primes_count(n):
return len([i for i in range(1, n) if gcd(n, i) == 1])
def get_phi(n):
return n / relative_primes_count(n)
def euler_069():

106
python/e070.py Normal file
View File

@ -0,0 +1,106 @@
from lib_misc import gcd
from lib_misc import is_permutation
class Primes(object):
def __init__(self, n_max):
import bitarray
self.n_max = n_max
b = bitarray.bitarray(n_max)
b.setall(True)
n = 1
b[n - 1] = False
while n * n <= n_max:
if b[n - 1] is True:
for i in range(n + n, n_max + 1, n):
b[i - 1] = False
n += 1
self.b = b
def iter_down(self):
for i in range(self.n_max, 0, -1):
if self.b[i - 1]:
yield i
raise StopIteration
def iter_up(self):
for i in range(1, self.n_max + 1):
if self.b[i - 1]:
yield i
raise StopIteration
def iter_range(self, n_min, n_max):
for i in range(n_min, n_max + 1):
if self.b[i - 1]:
yield i
raise StopIteration
def is_prime(self, n):
if n > self.n_max:
raise Exception("n greater than n_max")
return self.b[n - 1]
def relative_primes_count_naiv(n):
return len([i for i in range(1, n) if gcd(n, i) == 1])
def relative_primes_count_factors(n, fs):
from itertools import combinations
rel_primes_count = n - 1 # n itself is not a relative prime
for f in fs:
rel_primes_count -= (n // f - 1)
for f_1, f_2 in combinations(fs, 2):
f = f_1 * f_2
rel_primes_count += (n // f - 1)
return rel_primes_count
def get_phi(n):
r = relative_primes_count_naiv(n)
return n / r
def get_phi_factors(n, fs):
r = relative_primes_count_factors(n, fs)
return n / r
def euler_070():
"""
I struggled harder than I should have with this problem. I realized
quickly that a prime can't be the solution because a prime minus one
cannot be a permutation of itself. I then figured that the solution is
probably a number with two prime factors. I implemented an algorithm, but
it did not yield the right solution.
I tried a couple of things like squaring one prime factor which does not
yield a solution at all and three factors. Finally, I came up with a
faster algorithm to get the number of relative primes faster. With that
procedure I was then able to bruteforce the problem in 10 minutes.
When analyzing the solution I saw that it actually consists of two primes
which means my orginal algorithm had a bug. After reimplenting it was able
to find the solution in under 30 seconds. We could further optimize this
by making the search range for the two factors smaller. """
n = 10**7
ps = Primes(n // 1000)
phi_min = 1000
n_phi_min = 0
for p_1 in ps.iter_down():
for p_2 in ps.iter_range(1000, n // 1000):
n_new = p_1 * p_2
if n_new > n:
break
rel_primes_n_new = relative_primes_count_factors(n_new, [p_1, p_2])
phi_new = n_new / rel_primes_n_new
if phi_new < phi_min and is_permutation(n_new, rel_primes_n_new):
phi_min = phi_new
n_phi_min = n_new
return n_phi_min
if __name__ == "__main__":
print("e070.py: " + str(euler_070()))
assert(euler_070() == 8319823)

8
python/e071.py Normal file
View File

@ -0,0 +1,8 @@
def euler_071():
return 0
if __name__ == "__main__":
print("e071.py: " + str(euler_071()))
assert(euler_071() == 0)

8
python/e072.py Normal file
View File

@ -0,0 +1,8 @@
def euler_072():
return 0
if __name__ == "__main__":
print("e072.py: " + str(euler_072()))
assert(euler_072() == 0)

8
python/e073.py Normal file
View File

@ -0,0 +1,8 @@
def euler_073():
return 0
if __name__ == "__main__":
print("e073.py: " + str(euler_073()))
assert(euler_073() == 0)

8
python/e074.py Normal file
View File

@ -0,0 +1,8 @@
def euler_074():
return 0
if __name__ == "__main__":
print("e074.py: " + str(euler_074()))
assert(euler_074() == 0)

8
python/e075.py Normal file
View File

@ -0,0 +1,8 @@
def euler_075():
return 0
if __name__ == "__main__":
print("e075.py: " + str(euler_075()))
assert(euler_075() == 0)

View File

@ -1,5 +1,5 @@
FROM = 68
TILL = 68
FROM = 70
TILL = 75
template = """
def euler_XXX():

View File

@ -206,3 +206,14 @@ def get_digit_count(n):
Returns the number of digits for n.
"""
return len(str(n))
def is_permutation(n, p):
""" Checks if p is a permutation of n. """
digit_counts_n = [0 for _ in range(10)]
digit_counts_p = [0 for _ in range(10)]
for d_n in str(n):
digit_counts_n[int(d_n)] += 1
for p_n in str(p):
digit_counts_p[int(p_n)] += 1
return digit_counts_n == digit_counts_p

View File

@ -14,6 +14,7 @@ try:
from .lib_misc import permutations
from .lib_misc import gcd
from .lib_misc import get_digit_count
from .lib_misc import is_permutation
except ModuleNotFoundError:
from lib_misc import is_palindrome_integer
from lib_misc import is_palindrome_string
@ -29,6 +30,7 @@ except ModuleNotFoundError:
from lib_misc import permutations
from lib_misc import gcd
from lib_misc import get_digit_count
from lib_misc import is_permutation
class TestPrimeMethods(unittest.TestCase):
@ -137,6 +139,12 @@ class TestPrimeMethods(unittest.TestCase):
self.assertEqual(get_digit_count(1), 1)
self.assertEqual(get_digit_count(1234567890), 10)
def test_is_permutation(self):
self.assertTrue(is_permutation(123, 321))
self.assertTrue(is_permutation(123, 321))
self.assertFalse(is_permutation(12, 321))
self.assertFalse(is_permutation(1235, 4321))
if __name__ == '__main__':
unittest.main()