Euler has design of a homepage and there is a link back to the overview for each solution.
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<title>EulerProblem014</title><script src="https://cdnjs.cloudflare.com/ajax/libs/require.js/2.1.10/require.min.js"></script>
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<h1 id="Euler-Problem-14">Euler Problem 14<a class="anchor-link" href="#Euler-Problem-14">¶</a></h1><p>The following iterative sequence is defined for the set of positive integers:</p>
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<h1 id="Euler-Problem-14">Euler Problem 14<a class="anchor-link" href="#Euler-Problem-14">¶</a></h1><p><a href="/euler">Back to overview.</a></p><p>The following iterative sequence is defined for the set of positive integers:</p>
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<p>n → n/2 (n is even)
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n → 3n + 1 (n is odd)</p>
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<p>Using the rule above and starting with 13, we generate the following sequence:</p>
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@@ -11783,7 +11778,6 @@ n → 3n + 1 (n is odd)</p>
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<p>It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. Although it has not been proved yet (Collatz Problem), it is thought that all starting numbers finish at 1.</p>
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<p>Which starting number, under one million, produces the longest chain?</p>
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<p>NOTE: Once the chain starts the terms are allowed to go above one million.</p>
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@@ -11792,15 +11786,14 @@ n → 3n + 1 (n is odd)</p>
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<p>I would go for a recursive function with a cache here. This should give us good performance with acceptable memory footprint.</p>
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<div class=" highlight hl-ipython3"><pre><span></span><span class="kn">from</span> <span class="nn">functools</span> <span class="k">import</span> <span class="n">lru_cache</span>
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<span class="kn">from</span> <span class="nn">collections</span> <span class="k">import</span> <span class="n">deque</span>
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@@ -11814,62 +11807,50 @@ n → 3n + 1 (n is odd)</p>
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<span class="k">assert</span><span class="p">(</span><span class="nb">list</span><span class="p">(</span><span class="n">get_collatz_sequence</span><span class="p">(</span><span class="mi">13</span><span class="p">))</span> <span class="o">==</span> <span class="p">[</span><span class="mi">13</span><span class="p">,</span> <span class="mi">40</span><span class="p">,</span> <span class="mi">20</span><span class="p">,</span> <span class="mi">10</span><span class="p">,</span> <span class="mi">5</span><span class="p">,</span> <span class="mi">16</span><span class="p">,</span> <span class="mi">8</span><span class="p">,</span> <span class="mi">4</span><span class="p">,</span> <span class="mi">2</span><span class="p">,</span> <span class="mi">1</span><span class="p">])</span>
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<p>Isn't this a beautiful solution? We need a deque to appendleft. Of course, we could also use a regular list and reverse the result, but it is nicer to get the correct solution out right away. Now we simply force the solution.</p>
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<div class=" highlight hl-ipython3"><pre><span></span><span class="k">try</span><span class="p">:</span>
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<span class="n">s</span> <span class="o">=</span> <span class="nb">max</span><span class="p">([(</span><span class="nb">len</span><span class="p">(</span><span class="n">get_collatz_sequence</span><span class="p">(</span><span class="n">i</span><span class="p">)),</span> <span class="n">i</span><span class="p">)</span> <span class="k">for</span> <span class="n">i</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="mi">1000000</span><span class="p">)])</span>
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<span class="nb">print</span><span class="p">(</span><span class="n">s</span><span class="p">)</span>
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<span class="k">assert</span><span class="p">(</span><span class="n">s</span> <span class="o">==</span> <span class="mi">837799</span><span class="p">)</span>
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<span class="k">except</span> <span class="n">RecursionError</span><span class="p">:</span>
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<span class="nb">print</span><span class="p">(</span><span class="s2">"Okay, we need a loop."</span><span class="p">)</span>
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<span class="nb">print</span><span class="p">(</span><span class="s2">"Okay, we need a loop."</span><span class="p">)</span>
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<pre>Okay, we need a loop.
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<div class=" highlight hl-ipython3"><pre><span></span><span class="n">cache</span> <span class="o">=</span> <span class="p">{}</span>
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<span class="k">def</span> <span class="nf">get_collatz_sequence</span><span class="p">(</span><span class="n">n</span><span class="p">):</span>
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<span class="nb">print</span><span class="p">(</span><span class="n">timeit</span><span class="o">.</span><span class="n">timeit</span><span class="p">(</span><span class="n">brute_force</span><span class="p">,</span> <span class="n">number</span><span class="o">=</span><span class="mi">10</span><span class="p">))</span>
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<span class="nb">print</span><span class="p">(</span><span class="n">brute_force</span><span class="p">())</span>
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<pre>11.4885111964837
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837799
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<p>Here we go. Takes some time. We could optimize by caching only the length and not the complete list.</p>
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