Euler has design of a homepage and there is a link back to the overview for each solution.

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-<h1 id="Euler-Problem-9">Euler Problem 9<a class="anchor-link" href="#Euler-Problem-9">&#182;</a></h1><p>A Pythagorean triplet is a set of three natural numbers, $a &lt; b &lt; c$, for which,</p>
+<h1 id="Euler-Problem-9">Euler Problem 9<a class="anchor-link" href="#Euler-Problem-9">¶</a></h1><p><a href="/euler">Back to overview.</a></p><p>A Pythagorean triplet is a set of three natural numbers, $a &lt; b &lt; c$, for which,</p>
 <p>$a^2 + b^2 = c^2$</p>
 <p>For example, $3^2 + 4^2 = 9 + 16 = 25 = 5^2$.</p>
 <p>There exists exactly one Pythagorean triplet for which $a + b + c = 1000$.
 Find the product $abc$.</p>
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 <p>We start bruteforcing even though it feels like there may be a smart solution.</p>
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 <div class=" highlight hl-ipython3"><pre><span></span><span class="kn">import</span> <span class="nn">timeit</span>

 <span class="k">def</span> <span class="nf">brute_force</span><span class="p">():</span>
@@ -11810,45 +11803,35 @@ Find the product $abc$.</p>
 <span class="nb">print</span><span class="p">(</span><span class="n">timeit</span><span class="o">.</span><span class="n">timeit</span><span class="p">(</span><span class="n">brute_force</span><span class="p">,</span> <span class="n">number</span><span class="o">=</span><span class="mi">10</span><span class="p">))</span>
 <span class="nb">print</span><span class="p">(</span><span class="n">brute_force</span><span class="p">())</span>
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 <pre>66.96907186399949
 31875000
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 <p>Let's do some optimization by cancelling the loops when we exceed the boundaries. Actually, I have also realized that choosing 251 and 501 is a little bit arbitrary. For example if a, b, c where something like $332, 333, 335$ that could be a solution and the first range was too low. Then again, we would have realized that as soon as we get back None, so it is okay.</p>
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 <div class=" highlight hl-ipython3"><pre><span></span><span class="k">def</span> <span class="nf">brute_force</span><span class="p">():</span>
    <span class="k">for</span> <span class="n">a</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="mi">1</span><span class="p">,</span> <span class="mi">251</span><span class="p">):</span>
        <span class="k">for</span> <span class="n">b</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="n">a</span> <span class="o">+</span> <span class="mi">1</span><span class="p">,</span> <span class="mi">501</span><span class="p">):</span>
@@ -11861,45 +11844,35 @@ Find the product $abc$.</p>
 <span class="nb">print</span><span class="p">(</span><span class="n">timeit</span><span class="o">.</span><span class="n">timeit</span><span class="p">(</span><span class="n">brute_force</span><span class="p">,</span> <span class="n">number</span><span class="o">=</span><span class="mi">10</span><span class="p">))</span>
 <span class="nb">print</span><span class="p">(</span><span class="n">brute_force</span><span class="p">())</span>
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 <pre>64.4656584559998
 31875000
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 <p>Big time save. Kappa. Okay, I am stupid. If I have a and b I can calculate c and check if it is a solution.</p>
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 <div class=" highlight hl-ipython3"><pre><span></span><span class="k">def</span> <span class="nf">smart_brute_force</span><span class="p">():</span>
    <span class="k">for</span> <span class="n">a</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="mi">1</span><span class="p">,</span> <span class="mi">251</span><span class="p">):</span>
        <span class="k">for</span> <span class="n">b</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="n">a</span> <span class="o">+</span> <span class="mi">1</span><span class="p">,</span> <span class="mi">501</span><span class="p">):</span>
@@ -11910,49 +11883,34 @@ Find the product $abc$.</p>
 <span class="nb">print</span><span class="p">(</span><span class="n">timeit</span><span class="o">.</span><span class="n">timeit</span><span class="p">(</span><span class="n">smart_brute_force</span><span class="p">,</span> <span class="n">number</span><span class="o">=</span><span class="mi">10</span><span class="p">))</span>
 <span class="nb">print</span><span class="p">(</span><span class="n">smart_brute_force</span><span class="p">())</span>  
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 <pre>0.22822808900036762
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