Started to try 35.
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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Euler Problem 35\n",
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"\n",
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"The number, 197, is called a circular prime because all rotations of the digits: 197, 971, and 719, are themselves prime.\n",
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"\n",
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"There are thirteen such primes below 100: 2, 3, 5, 7, 11, 13, 17, 31, 37, 71, 73, 79, and 97.\n",
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"\n",
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"How many circular primes are there below one million?"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"First we get all primes into a look-up table. Then we iterate them and check whether they are circular."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 23,
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"metadata": {
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"collapsed": false
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"78498\n"
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]
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}
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],
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"source": [
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"def get_primes_smaller(number):\n",
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" primes = []\n",
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" prospects = [n for n in range(2, number)]\n",
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" while prospects:\n",
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" p = prospects[0]\n",
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" prospects = [x for x in prospects if x % p != 0]\n",
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" primes.append(p)\n",
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" if p * p > number:\n",
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" return primes + prospects\n",
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" return primes\n",
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"\n",
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"ps = get_primes_smaller(1000000)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 24,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"def get_combinations(xs):\n",
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" if not xs:\n",
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" return []\n",
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" rs = []\n",
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" for i in range(len(xs)):\n",
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" yss = get_combinations(xs[:i] + xs[i + 1:])\n",
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" if not yss:\n",
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" rs.append(xs[i])\n",
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" for ys in yss:\n",
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" rs.append(xs[i] + ys)\n",
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" return rs\n",
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"\n",
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"assert(get_combinations(\"ab\") == [\"ab\", \"ba\"])"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 25,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"from itertools import permutations\n",
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"prime_set = set(ps)\n",
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"\n",
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"def is_circular(p):\n",
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" cs = permutations(str(p))\n",
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" for c in cs:\n",
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" if not int(\"\".join(c)) in prime_set:\n",
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" return False\n",
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" return True\n",
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"\n",
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"assert(is_circular(\"2\") == True)\n",
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"assert(is_circular(\"11\") == True)\n",
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"assert(is_circular(\"47\") == False)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 26,
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"metadata": {
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"collapsed": true
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},
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"outputs": [],
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"source": [
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"s = [p for p in ps if is_circular(p)]"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 28,
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"metadata": {
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"collapsed": false
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"[2, 3, 5, 7, 11, 13, 17, 31, 37, 71, 73, 79, 97, 113, 131, 199, 311, 337, 373, 733, 919, 991]\n"
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]
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}
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],
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"source": [
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"print(s)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {
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"collapsed": true
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},
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"outputs": [],
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"source": []
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.5.4"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 0
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}
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