euler/ipython/EulerProblem001.ipynb

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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Euler Problem 1\n",
"\n",
"If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.\n",
"\n",
"Find the sum of all the multiples of 3 or 5 below 1000."
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"def get_sum_of_natural_dividable_by_3_and_5_below(m):\n",
" return sum([x for x in range(m) if x % 3 == 0 or x % 5 == 0])"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Test example provided in problem statement:"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"assert(get_sum_of_natural_dividable_by_3_and_5_below(10) == 23)"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"233168\n"
]
}
],
"source": [
"print(get_sum_of_natural_dividable_by_3_and_5_below(1000))"
]
}
],
"metadata": {
"completion_date": "Tue, 19 Aug 2014, 20:11",
"kernelspec": {
"display_name": "Python 3",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.5.4"
},
"tags": [
2018-02-04 21:00:20 +01:00
"brute force"
]
},
"nbformat": 4,
"nbformat_minor": 2
}