# Euler Problem 20¶

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n! means n × (n − 1) × ... × 3 × 2 × 1

For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800, and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.

Find the sum of the digits in the number 100!

Write our own factorial implementation and get the solution.

In [1]:

    def factorial(n):
        assert(n > 0)
        if n == 1:
            return 1
        else:
            return n * factorial(n - 1)

In [2]:

    f100 = factorial(100)
    print(sum(map(int, str(f100))))
    assert(sum(map(int, str(f100))) == 648)

    648