Implement dynamic programming solution for Knapsack.
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knapsack/knapsack.py
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89
knapsack/knapsack.py
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from collections import namedtuple
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Result = namedtuple("Result", ['objective', 'is_optimal', 'xs'])
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Item = namedtuple("Item", ['index', 'value', 'weight'])
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Knapsack = namedtuple("Knapsack", ['count', 'capacity', 'items'])
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def solve_knapsack_greedy(knapsack):
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remaining_capacity = knapsack.capacity
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current_value = 0
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xs = [0] * knapsack.count
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for item in knapsack.items:
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if remaining_capacity >= item.weight:
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remaining_capacity -= item.weight
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current_value += item.value
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xs[item.index] = 1
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return Result(current_value, 0, xs)
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def solve_knapsack_dynamic(knapsack):
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value_column = [0 for _ in range(knapsack.capacity + 1)]
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# Keep track for each item for what capacities we take
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# the respective item. This allows us to backtrack the items
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# for the optimal solution later.
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item_taken = {i: set() for i in range(len(knapsack.items))}
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for item in knapsack.items:
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new_column = list(value_column)
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for capacity in range(knapsack.capacity + 1):
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if item.weight <= capacity:
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# Calculate the new value for the capacity if we take the item.
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new_value = item.value + value_column[capacity - item.weight]
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if new_value > value_column[capacity]:
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new_column[capacity] = new_value
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item_taken[item.index].add(capacity)
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# There is no else case because new_colum contains the right values
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# from the previous item so we only have to update when the new
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# value is better.
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value_column = new_column
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objective = value_column[-1]
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# Dynamic programing computes the best posible solution.
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is_optimal = 1
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# Reconstruct which items are used for the optimal solution.
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xs = []
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current_index = knapsack.items[-1].index
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current_capacity = knapsack.capacity
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while current_index >= 0:
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if current_capacity in item_taken[current_index]:
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current_capacity -= knapsack.items[current_index].weight
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xs.append(1)
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else:
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xs.append(0)
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current_index -= 1
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xs.reverse()
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return Result(objective, is_optimal, xs)
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def solve_knapsack_depth_first_search(knapsack):
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objective = 0
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pass
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def input_data_to_knapsack(input_data):
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lines = input_data.split('\n')
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item_count, capacity = map(int, lines[0].split())
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items = []
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for i in range(1, item_count + 1):
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line = lines[i]
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value, weight = map(int, line.split())
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items.append(Item(i-1, value, weight))
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k = Knapsack(item_count, capacity, items)
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return k
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def result_to_output_data(result):
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# prepare the solution in the specified output format
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output_data = str(result.objective) + ' ' + str(result.is_optimal) + '\n'
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output_data += ' '.join(map(str, result.xs))
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return output_data
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#!/usr/bin/python
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# -*- coding: utf-8 -*-
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from collections import namedtuple
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Item = namedtuple("Item", ['index', 'value', 'weight'])
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import knapsack
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def solve_it(input_data):
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# Modify this code to run your optimization algorithm
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# parse the input
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lines = input_data.split('\n')
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firstLine = lines[0].split()
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item_count = int(firstLine[0])
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capacity = int(firstLine[1])
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items = []
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for i in range(1, item_count+1):
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line = lines[i]
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parts = line.split()
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items.append(Item(i-1, int(parts[0]), int(parts[1])))
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# a trivial greedy algorithm for filling the knapsack
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# it takes items in-order until the knapsack is full
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value = 0
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weight = 0
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taken = [0]*len(items)
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for item in items:
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if weight + item.weight <= capacity:
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taken[item.index] = 1
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value += item.value
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weight += item.weight
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# prepare the solution in the specified output format
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output_data = str(value) + ' ' + str(0) + '\n'
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output_data += ' '.join(map(str, taken))
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return output_data
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k = knapsack.input_data_to_knapsack(input_data)
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if k.count * k.capacity < 50000000:
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r = knapsack.solve_knapsack_dynamic(k)
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else:
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r = knapsack.solve_knapsack_greedy(k)
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return knapsack.result_to_output_data(r)
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if __name__ == '__main__':
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@ -47,5 +22,7 @@ if __name__ == '__main__':
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input_data = input_data_file.read()
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print(solve_it(input_data))
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else:
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print('This test requires an input file. Please select one from the data directory. (i.e. python solver.py ./data/ks_4_0)')
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print("This test requires an input file. "
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"Please select one from the data directory. "
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"(i.e. python solver.py ./data/ks_4_0)")
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