(load "util.scm")

(display "ex-1.29") (newline)

(define (sum term a next b)
  (if (> a b)
      0
      (+ (term a)
         (sum term (next a) next b))))

(define (sum-cubes a b)
  (sum cube a inc b))

(display "(sum-cubes 1 10) = ")
(display (sum-cubes 1 10))
(newline)

(define (pi-sum a b)
  (define (pi-term n) (/ 1.0 (* n (+ n 2))))
  (define (pi-next n) (+ n 4))
  (sum pi-term a pi-next b))

(display "(* 8 (pi-sum 1 100)) = ")
(display (* 8 (pi-sum 1 100)))
(newline)


(define (integral f a b dx)
  (define (add-dx x) (+ x dx))
  (* (sum f (+ a (/ dx 2.0)) add-dx b)
     dx))

(display "(integral cube 0 1 0.01) = ")
(display (integral cube 0 1 0.01))
(newline)

(define (integral-simpson f a b n)
  (define h (/ (- b a) n))
  (define (y k) (f (+ a (* k h))))
  (define (simpson-term k)
    (cond ((= k 0) (y 0))
          ((= k n) (y k))
          ((even? k) (* 2 (y k)))
          (else (* 4 (y k)))))
  (* (/ h 3) (sum simpson-term 0 inc n)))

(display "(integral-simpson cube 0 1 100) = ")
(display (integral-simpson cube 0 1 100))
(newline)

(newline) (display "ex-1.30") (newline)

; maximum recursion dept exceed
(display (* 8 (pi-sum 1 1000000)))

(define (sum term a next b)
  (define (sum-iter a acc)
    (if (> a b)
      acc
      (sum-iter (next a) (+ acc (term a)))))
  (sum-iter a 0))

(newline)
(display "(* 8 (pi-sum 1 1000000)) = ")
(display (* 8 (pi-sum 1 1000000)))

(newline)(newline) (display "ex-1.31") (newline)
(define (product term a next b)
  (if (> a b)
    1
    (* (term a) (product term (next a) next b))))

(define (factorial n)
  (product identity 1 inc n))

(display "(factorial 10) = ")
(display (factorial 10))
(newline)

(define (pi-product n)
  (define (pi-term n) (/ (* n (+ n 2.)) (square (+ n 1.))))
  (define (pi-next n) (+ n 2))
  (product pi-term 2 pi-next n))

(display "(* 4 (pi-product 1000000)) = ")
(display (* 4 (pi-product 1000000)))

(define (product term a next b)
  (define (product-iter term a next b acc)
    (if (> a b)
      acc
      (product-iter term (next a) next b (* acc (term a)))))
  (product-iter term a next b 1))

(newline)
(display "(* 4 (pi-product 1000000)) = ")
(display (* 4 (pi-product 1000000)))

(newline)(newline) (display "ex-1.32") (newline)

(define (mul-op a b) (* a b))
(define (sum-op a b) (+ a b))

; Recursive
(define (accumulate combiner null-value term a next b)
  (if (> a b) null-value
    (combiner (term a) (accumulate combiner null-value term (next a) next b))))

(define (sum term a next b)
  (accumulate sum-op 0 term a next b))

(define (product term a next b)
  (accumulate mul-op 1 term a next b))

(display (sum identity 1 inc 10)) (newline)
(display (product identity 1 inc 10)) (newline)

(display "(* 4 (pi-product 1000000)) = ")
(display (* 4 (pi-product 1000000)))

; Iterative
(define (accumulate combiner null-value term a next b)
  (define (acc-iter a acc)
    (if (> a b)
      acc
      (acc-iter (next a) (combiner acc (term a)))))
  (acc-iter a null-value))

(newline)
(display "(* 4 (pi-product 1000000)) = ")
(display (* 4 (pi-product 1000000)))


(newline)(newline) (display "ex-1.33") (newline)

(define (filtered-accumulate combiner null-value filter term a next b)
  (define (combiner-filtered acc a)
    (if (filter a)
      (combiner acc (term a))
      acc))
  (define (iter a acc)
    (if (> a b)
      acc
      (iter (next a) (combiner-filtered acc a))))
  (iter a null-value))


(define (primes-squared-sum a b)
  (filtered-accumulate sum-op 0 prime? square a inc b))

(display (primes-squared-sum 1 5)) (newline) ; expected 38

(define (product-integers-coprime n)
  (define (filter a) (= (gcd n a) 1))
  (filtered-accumulate mul-op 1 filter identity 1 inc (- n 1)))

(display (product-integers-coprime 10)) (newline) ; expected 189


(newline) (display "ex-1.34 - see comment") (newline)

; Exercise 1.34. Suppose we define the procedure (define (f g) (g 2)).  What
; happens if we (perversely) ask the interpreter to evaluate the combination
; (f ; f)? Explain.

; The result would be (2 2) and 2 is not applicable.