2020-12-31 22:38:21 +01:00
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(load "util.scm")
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2021-01-01 14:40:12 +01:00
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(display "\nex-3.50 - stream-map\n")
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2020-12-31 22:38:21 +01:00
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2021-01-01 14:40:12 +01:00
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(define (stream-enumerate-interval low high)
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(if (> low high)
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the-empty-stream
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(cons-stream
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low
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(stream-enumerate-interval (+ low 1) high))))
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(define (stream-map proc . argstreams)
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(if (stream-null? (car argstreams))
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the-empty-stream
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(cons-stream
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(apply proc (map stream-car argstreams))
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(apply stream-map
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(cons proc (map stream-cdr argstreams))))))
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(define (stream-to-list xs)
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(if (stream-null? xs)
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'()
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(cons (stream-car xs)
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(stream-to-list (stream-cdr xs)))))
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(assert (stream-to-list (stream-enumerate-interval 1 3))
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'(1 2 3))
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(assert (stream-to-list
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(stream-map (lambda (x y) (* x y))
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(stream-enumerate-interval 1 3)
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(stream-enumerate-interval -3 -1)))
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'(-3 -4 -3))
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(display "\nex-3.51\n")
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(define (show x)
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(display-line x)
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x)
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(define (stream-ref s n)
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(if (= n 0)
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(stream-car s)
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(stream-ref (stream-cdr s) (- n 1))))
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(define x (stream-map show (stream-enumerate-interval 0 10)))
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(stream-ref x 5)
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; 0
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; 1
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; 2
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; 3
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; 4
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; 5
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(stream-ref x 7)
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; 6
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; 7
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(display "\nex-3.52\n")
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(define (display-stream s)
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(stream-for-each display-line s))
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(define sum 0)
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(define (accum x)
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(set! sum (+ x sum))
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sum)
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(define seq (stream-map accum (stream-enumerate-interval 1 20)))
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; 1 3 6 10 15 21 28 36 45 55 66 78 91 105 120 136 153 171 190 210
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(define y (stream-filter even? seq))
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; 6 10 28 36 66 78 120 136 190 210
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(define z (stream-filter (lambda (x) (= (remainder x 5) 0))
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seq))
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(assert (stream-ref y 7) 136)
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(assert (stream-to-list z)
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'(10 15 45 55 105 120 190 210))
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; The responses would differ if we had implemented delay without memo-proc,
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; because the values of the stream would be recomputed for z starting from the
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; last value of sum after defining y.
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(display "\nexample - sieve of Eratosthenes\n")
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(define (integers-starting-from n)
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(cons-stream n (integers-starting-from (+ n 1))))
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(define (divisible? x y) (= (remainder x y) 0))
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(define (sieve stream)
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(cons-stream
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(stream-car stream)
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(sieve (stream-filter
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(lambda (x)
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(not (divisible? x (stream-car stream))))
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(stream-cdr stream)))))
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(define primes (sieve (integers-starting-from 2)))
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(assert (stream-ref primes 5) 13)
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(display "\nex-3.53\n")
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2020-12-31 22:38:21 +01:00
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2021-01-02 11:08:12 +01:00
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(define (add-streams s1 s2)
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(stream-map + s1 s2))
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(define ones (cons-stream 1 ones))
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(define integers (cons-stream 1 (add-streams ones integers)))
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(define (take n xs)
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(if (= n 0)
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'()
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(cons (stream-car xs)
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(take (- n 1) (stream-cdr xs)))))
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(assert (take 3 integers)
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'(1 2 3))
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(define fibs
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(cons-stream 0
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(cons-stream 1
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(add-streams (stream-cdr fibs)
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fibs))))
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(assert (take 7 fibs)
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'(0 1 1 2 3 5 8))
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(define (scale-stream stream factor)
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(stream-map (lambda (x) (* x factor)) stream))
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(define double (cons-stream 1 (scale-stream double 2)))
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(assert (take 3 double)
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'(1 2 4))
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(define s (cons-stream 1 (add-streams s s)))
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(assert (take 5 s)
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'(1 2 4 8 16))
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(display "\nex-3.54 - factorials\n")
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(define (mul-streams s1 s2)
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(stream-map * s1 s2))
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(define factorials (cons-stream 1 (mul-streams (stream-cdr integers) factorials)))
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(assert (take 5 factorials)
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'(1 2 6 24 120))
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(display "\nex-3.55 - partial-sums\n")
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(define (partial-sums xs)
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(cons-stream (stream-car xs)
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(add-streams (partial-sums xs)
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(stream-cdr xs))))
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(assert (take 5 (partial-sums integers))
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'(1 3 6 10 15))
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(display "\nex-3.56 - enumerate multiplies of 2, 3, 5\n")
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(define (merge s1 s2)
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(cond ((stream-null? s1) s2)
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((stream-null? s2) s1)
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(else
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(let ((s1car (stream-car s1))
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(s2car (stream-car s2)))
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(cond ((< s1car s2car)
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(cons-stream s1car (merge (stream-cdr s1) s2)))
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((> s1car s2car)
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(cons-stream s2car (merge s1 (stream-cdr s2))))
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(else
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(cons-stream s1car
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(merge (stream-cdr s1)
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(stream-cdr s2)))))))))
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(define S (cons-stream 1 (merge (merge (scale-stream S 2) (scale-stream S 3))
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(scale-stream S 5))))
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(assert (take 10 S)
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'(1 2 3 4 5 6 8 9 10 12))
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(display "\nex-3.57\n")
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2021-01-03 13:59:39 +01:00
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(display "[answered]\n")
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; With memoizing only one addition is required per number. So the complexity is
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; O(n). With memoizing the previous numbers have to be calculated recursively
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; which leads to exponential growth.
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(display "\nex-3.58 - expand\n")
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(define (expand num den radix)
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(cons-stream
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(quotient (* num radix) den)
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(expand (remainder (* num radix) den) den radix)))
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(assert (take 5 (expand 1 7 10))
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'(1 4 2 8 5))
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(assert (take 5 (expand 3 8 10))
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'(3 7 5 0 0))
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; The procedure expands a fraction (num/dem) into the rational value to base
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; radix.
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(display "\nex-3.59 - sine/cosine series\n")
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(define (integrate-series xs)
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(define (iter n xs)
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(cons-stream (* (/ 1 n) (stream-car xs))
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(iter (+ n 1) (stream-cdr xs))))
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(iter 1 xs))
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(define (integrate-series xs)
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(stream-map * (stream-map / ones integers) xs))
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(assert (take 5 (integrate-series integers))
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'(1 1 1 1 1))
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(define exp-series
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(cons-stream 1 (integrate-series exp-series)))
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(define (sum xs)
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(if (null? xs)
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0
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(+ (car xs) (sum (cdr xs)))))
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(assert (sum (take 5 exp-series))
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(/ 65 24))
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(define cosine-series
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(cons-stream 1 (stream-map - (integrate-series sine-series))))
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(define sine-series
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(cons-stream 0 (integrate-series cosine-series)))
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(assert (sum (take 10 sine-series))
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(/ 305353 362880))
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(display "\nex-3.60 - mul-series\n")
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(define add-series add-streams)
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(define (mul-series s1 s2)
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(cons-stream (* (stream-car s1) (stream-car s2))
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(add-streams (scale-stream (stream-cdr s2) (stream-car s1))
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(mul-series (stream-cdr s1) s2)))))
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(assert (sum (take 10 (add-series (mul-series cosine-series cosine-series)
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(mul-series sine-series sine-series))))
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1)
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(display "\nex-3.61 - invert-unit-series\n")
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(define (invert-unit-series s) 0)
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(display "\nex-3.62\n")
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2021-01-02 11:08:12 +01:00
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